Home
Class 11
PHYSICS
A beam of protons enters a uniform magne...

A beam of protons enters a uniform magnetic field of 0.3T with velocity of `4xx10^5m//s` in a direction making an angle of `60^(@)` with the direction of magnetic field. The path of motion of the particle will be

A

circular

B

Straight line

C

Spiral

D

helical

Text Solution

Verified by Experts

The correct Answer is:
D
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • KTG & THERMODYNAMICS

    RESONANCE|Exercise SUBJECTIVE QUESTIONS|27 Videos
  • NEWTONS LAWS OF MOTION AND FRICTION

    RESONANCE|Exercise Exercise|56 Videos

Similar Questions

Explore conceptually related problems

A beam of protons enters a uniform magnetic field of 0.3 T,with a velocity of 4xx10^(5)ms^(-5), in a direction making an angle of 60^(@) with the direction of magnetic field.Determine (i) the path of motion of the particles (ii) the radius of the path of the particles (iii) the pitch of the helix.

A beam of electrons enters a uniform magnetic field of 0*3T with a velocity of 4xx10^5ms^-1 at an angle of 60^@ to the field. Find the radius of the helical path taken by the beam. Also find the pitch of the helix (distance travelled by a proton parallel to the magnetic field during one period of rotation). Mass of proton is 1*67xx10^(-27)kg .

Knowledge Check

  • A charged particle enters into a magnetic field with velocity vector making an angle of 30^@ with respect of the direction of magnetic field. The path of the particle is

    A
    circular
    B
    helical
    C
    elliptical
    D
    straight line
  • A charged particle enters a magnetic field at an angle of 90^(@) with the magnetic field. The path of the particle will be a/an

    A
    Helix
    B
    Ellipse
    C
    Circle
    D
    Straight line
  • A proton enters a magnetic field of 1.5 T with a velocity of 2 xx 10^(7) ms^(-1) at an angle of 30^@ with the field. The force on the proton will be

    A
    `2.4 xx 10^(-12) N`
    B
    `0.24 xx 10^(-12) N`
    C
    `24 xx 10^(-12)N`
    D
    `0.024 xx 10^(-12) N`
  • Similar Questions

    Explore conceptually related problems

    A beam of protons enters a uniform magnetic field of 0.3 tesla with a velocity of 4xx10^(5) m/s at an angle of 60º to the field. Then, (Mass of the proton =1.7 xx10^(-27) kg.) (1) the radius of the helical path is 1.226 xx 10^(-2) m (2) the pitch of the helix is 4.45 xx 10^(-2) m (3) the radius of the helical path is 1.226 xx 10^(-3) m (4) the pitch of the helix is 4.45xx10^(-4) m

    A beam of protons with a velocity of 4 X 10 ^5 ms^(-1) enters a uniform magnetic field of 0.3 T. The velocity makes an angle of 60^@ with the magnetic field. Find the radius of the helicla path taken by the proton beam and the pitch of the helix.

    A proton moving with a velocity of 2.5 xx 10^(7) m/s , enter a magnetic feildof 2T, making an angle of 30◦ with the magnetic field. The force acting on the proton

    A proton enters a magnetic field with a velocity of 2.5 xx10^(7)ms^(-1) making an angle 30^(@) with the magnetic field. The force on the proton is (B=25T)

    A charged particle enters a uniform magnetic field with velocity vector at angle of 45^@ with the magnetic field. The pitch of the helical path followed by the particle is p. the radius of the helix will be