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A particle of charge per unit mass alpha...

A particle of charge per unit mass `alpha` is released from origin with a velocity `vecv=v_(0)hati` uniform magnetic field `vecB=-B_(0)hatk`. If the particle passes through `(0,y,0)`, then `y` is equal to

A

`-(2v_(0))/(B_(0)alpha)`

B

`(v_(0))/(B_(0)alpha)`

C

`(2v_(0))/(B_(0)alpha)`

D

`-(v_(0))/(B_(0)alpha)`

Text Solution

Verified by Experts

The correct Answer is:
C
Direction of force along +y direction, so particle passes through the +y axis at a distance 2r from origin.
`y=2r=(2mv)/(qB)=(2v_(0))/(B_(0)alpha)`
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