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A particle of mass 1.6xx10^(-27) kg and ...

A particle of mass `1.6xx10^(-27) kg` and charge `1.6 xx 10^(-19)` coulomb enters a uniform magnetic field of 1 Tesla as shown in the figure. The speed of the particle is `10^7 m//s`. The distance PQ will be

A

0.14 m

B

0.28 m

C

0.4 m

D

0.5 m

Text Solution

Verified by Experts

The correct Answer is:
A
`PQ=2r sin theta=2(mv)/(qB) sin theta=(2xx1.6xx10^(-27)xxsin45)/(1.6xx10^(-19)xx1)=2/(10sqrt(2)) =(sqrt(2))/10=0.14`
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