A particle having a charge`20mu C` and mass `20mug` moves along a circle of radius 5.0 cm under the action of a magnetic field 5.0 cm under the action of a magnetic field B = 1.0 T. When the particle is at a point P, a uniform electric field is switched on and it is found that the particla continues on the tangent through P qith a uniform velocity. Find the electric field.

Options

A. 0.1 V/m
B. 1.0 V/m
C. 10.0 V/m
D. 100 V/m

Answer

B

Explanation

`V=(qBr)/m=(10xx10^(-6)xx7xx10xx10^(-2))/(10^(-6)xx1)=1 m//s`
`E=BV=1xx1=1.0 V//m`