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A metallic rod completes its circuit as ...

A metallic rod completes its circuit as shown in the figure. The circuit is normal to a magnetic field of `B=0.15` tesla. If the resistances of the rod is `3Omega` the force required to move the rod with a constant velocity of `2m//sec` is-

A

`3.75xx10^(-3) N`

B

`3.75 xx10^(-2) N`

C

`3.75 xx10^(2) N`

D

`3.75 xx10^(-4) N`

Text Solution

Verified by Experts

The correct Answer is:
A
`e=Blv`
`i=e/R=(Blv)/R`
`F-iBl =0`
`F=iBl =3.75xx10^(-3) N`
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