The horizontal component of earth's magnetic field is `3xx10^(-5) Wb//m^2`. The magnetic flux linked with a coil of area `1m^2` and having 5 turns, whose plane is normal to the magnetic field, will be

Options

A. `3xx10^(-5) Wb`
B. `5xx10^(-5) Wb`
C. `15xx10^(-5) Wb`
D. zero

Answer

C

Explanation

`phi=NB_(H)A`