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The distance of n^(th) bright fringe to ...

The distance of `n^(th)` bright fringe to the `(n+1)^(th)` dark fringe in Young's experiment is equal to:

A

`(n lambdaD)/d`

B

`(nlambdaD)/(2d)`

C

`(lambdaD)/(2d)`

D

`(lambdaD)/d`

Text Solution

Verified by Experts

The correct Answer is:
C
The distance between nth bright finge and `(n+1)^(th)` dark fringe is equal to fringe width `=(lambdaD)/(2d)`
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