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The binding energies per nucleon for a d...

The binding energies per nucleon for a deuteron and an `alpha-`particle are `x_1` and `x_2` respectively. What will be the energy `Q` released in the following reaction ?
`._1H^2 + ._1H^2 rarr ._2He^4 + Q`.

A

`(x_(1)+x_(2))`

B

`(x_(2)-x_(1))`

C

`4(x_(1)-x_(2))`

D

`4(x_(2)-x_(1))`

Text Solution

Verified by Experts

The correct Answer is:
D
`(4x1.0089+5x1.009)-9.012=Deltam`
binding energy `=Deltamxxc^(2)`
Bindng energy /nucleon `=("Binding energy")//9=6.72 MeV`
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