The mean of life of a radioactive sample is 100 years. Then after 100 years, about-

Options

A. 0% of the sample remains active
B. 37% of the simple remains active
C. 63% of the sample remain active
D. 50 % of the sample remains active

Answer

B

Explanation

`t_("mean")=1/(lambda)=100 rArr N=N_(0) e^(-lambdat) =N_(0)//e=37 N_(0)`