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A radioactive element ThA( .(84)Po^(216)...

A radioactive element `ThA( ._(84)Po^(216))` can undergo `alpha` and `beta` are type of disintegrations with half-lives, `T_1` and `T_2` respectively. Then the half-life of ThA is

A

`T_(1)+T_(2)`

B

`T_(1)T_(2)`

C

`T_(1)-T_(2)`

D

`(T_(1)T_(2))/(T_(1)+T_(2))`

Text Solution

Verified by Experts

The correct Answer is:
D


`i=I_(1)+I_(2)`
`(ln2)/T=(ln2)/(T_(1))+(ln2)/(T_(2))rArr T=(T_(1))/(T_(1))+(T_(2))/(T_(2))`
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