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A stone of mass M is tied at the end of ...

A stone of mass M is tied at the end of a string, is moving in a circle of radius R, with a constant angular velocity `omega`. The total work done on the stone, in any half circle, is:

A

`piMR^(2) omega^(2)`

B

`2 MR^(2) omega^(2)`

C

`MR^(2) omega^(2)`

D

0

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Verified by Experts

The correct Answer is:
D
Since there is no change in kinetic energy of stone, the total work done on stone in any duration is zero.
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