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Two constant horizontal force F1 and F2 ...

Two constant horizontal force `F_1` and `F_2` are acting on blocks A and B. At an instant acceleration of block B is `4m//s^2` in direction of `F_1` and acceleration of block A w.r.t block B at this moment is:

A

`1 m//s^(2)`

B

`2 m//s^(2)`

C

`7 m//s^(2)`

D

`9 m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`F_("net")=m_(1)a_(1)+m_(2)a_(2)rArr 100-70=5xx4+2xxarArr a=5m//s^(2)`
So, `a_("rel")=5-4 =1 m//s^(2)`
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Knowledge Check

  • If block A is moving with an acceleration of 5ms^(-2) , the acceleration of B w.r.t. ground is

    A
    `5ms^(-2)`
    B
    `5sqrt(2)ms^(-2)`
    C
    `5sqrt(5)ms^(-2)`
    D
    `10ms^(-2)`

  • A horizontal force F acts on the block of mass m and the block remains stationary, thr value of friction force is.

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    `mumg`
    B
    `mumg-F`
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    F
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    zero

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