At pressure P and absolute temperature T a mass M of an ideal gas fills a closed container of volume V. An additional mass 2M of the same gas is added into the container and the volume is then reduced to `V/3` and the temperature to `T/3`. The pressure of the gas will now be:

Options

A. `P/3`
B. P
C. 3P
D. 9P

Answer

C

Explanation

If `M_(0)` is molecular mass of the gas then for final condition `PV'=M/(M_(0)).RT....(1)`
After 2M mass has been added
`P'.V/3 =(3M)/(M_(0)).R.T/3...(2)`
By dividing (2) by (1) `rArr P'=3P`