One litre of helium gas at a pressure `76 cm`. Of Hg and temperature `27^(@)C` is heated till its pressure and volume are double. The final temperature attained by the gas is:

Options

A. `327^(@)C`
B. `927^(@)C`
C. `1027^(@)C`
D. `827^(@)C`

Answer

B

Explanation

Initial volume of the gas `V_(1)=1` litre pressure of the gas `P_(1)`=70 cm of Hg
Final pressure of the gas `P_(2)=2xx76=152 cm `of Hg
Final volume of the gas `V_(2)=2` litre
According the Gay Lussac law we have
`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))` or `(76xx1)/300=(152xx2)/(T_(2))`
`1/300=4/(T_(2))` or `T_(2)=4xx300=1200 K =927^(@)C`