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Two rods of same length and areas of cross section `A_1` and `A_2` have their ends at same temperature. If `K_1` and `K_2` are their thermal conductivities, `C_1` and `C_2` their specific heats and `rho_1` and `rho_2` are their densities, then the condition that rate of flow of heat is same in both the rods is

A

`A_(1)//A_(2)=K_(1)//K_(2)`

B

`A_(1)//A_(2)=K_(1)C_(1)rho_(1)//K_(2) C_(2)rho_(2)`

C

`A_(1)//A_(2)=K_(2)C_(1)rho_(1)//K_(1)C_(2)rho_(2)`

D

`A_(1)//A_(2)=K_(2)//K_(1)`

Text Solution

Verified by Experts

The correct Answer is:
D

`L/(K_(1)A_(1))=L/(K_(2)A_(2))`
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