A particle moving on x - axis has potential energy `U = 2 - 20x + 5x^(2)` joule along x - axis. The particle is relesed at `x = -3`. The maximum value of `x` will be (`x` is in metre)

Options

A. 5m
B. 3m
C. 7m
D. 8m

Answer

C

Explanation

`U=2-20x+5x^(2)`
`F=-(dU)/(dx)=20-10 x `
At equilibrium position , F=0
`20-10 x=0`
`rArr x=2`
Since particle is released at x=-3, therefore amplitude of particle is 5.

It will oscillate about x=2 with an amplitude of 5.
`:. ` maximum value of x will be 7.