Figure shows a solid hemisphere with a charge of 5 nC distributed uniformly through its volume. The hemisphere lies on a plane and point P is located on the plane, along a radial line from the centre of curvature at distance 15 cm. The electric potential at point P due to the hemisphere is:

Options

A. 150 V
B. 300 V
C. 450 V
D. 600 V

Answer

B

Explanation

By symmetry (it will be half of the potential produces by the full sphere)
`rArr 1/2.(K(2Q))/R=(KQ)/RrArr V=(KQ)/R =(9xx10^(9)xx5xx10^(-9))/(15xx10^(-2)) =300V`