In the figure two concentric conducting shells of radius R & 2R are shown. The inner shell is charged with Q and the shell is unchanged. The amount of energy dissipated when the shells are connected by a conducting wire is:

Options

A. `(KQ^(2))/(4R)`
B. `(kQ^(2))/(2R)`
C. `(kQ^(2))/(8R)`
D. `(3kQ^(2))/4`

Answer

A

Explanation

`U_(i)=(KQ^(2))/(2R) U_(t)=(KQ^(2))/(2(2R))`
(whole charge will get transformed to outer sphere)
so heat `=(KQ^(2))/(2(2R)) =(KQ^(2))/(4R)`