Calculate the binding energy of an alpha particle from the following data:
`mass of _1^1H atom = 1.007825 u`
mass of neutron `= 1.008665 u`
mass of `_4^2He atom = 4.00260 u`.
Take `1 u = 931 MeV c^(-2)`

Explanation

The alpha particle contains `2` protons and `2` neutrons. The binding energy is
`B = (2 xx 1.007826 u + 2 xx 1.008665 u - 4.00260 u)c^(2)`
`= (0.03038 u)c^(2)`
`= 0.03038 xx 931 Me V = 28.3 Me V`.