In the decay `Cu^64 rarr Ni^64 + e^+ + v`,
the maximum kinetic energy carried by the netrino which was emitted together with a positron of kinetic energy 0.150 meV? (a) what is the energy of the neutrino which was emitted togather with a positron of kinetic energy 0.150 MeV ? .(b)What is the momentum of this neutrino in kg m `s^(-1)`?Use the formula applicable to photon.

Answer

(a) `(0.680-0.180)Me V =500 keV`
(b) `(500xx10^(3)e)/(c )=2.67xx10^(-22)kg-m//s`

Explanation

(a) `KE "of"upsilon+KE "of"e^(+)= "Maximum energy of"e^(+)`
`rArrKE "of" upsilon=(0.680-0.180)MeV=500KeV`.
(b) `p=(E )/(C )=(500xx10^(3)xx1.6xx10^(-19))/(3xx10^(8))Kg-m//s=2.67xx10^(-22)Kg-m//s`.