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Energy evolved from the fusion reaction ...

Energy evolved from the fusion reaction `2_(1)^(2)H=_(1)^(4)He+Q` is to be used for the production of power. Assuming the efficiency of the process to be `30%`. Find the mass of deuterium that will be consumed in a second for an output of `50 MW`.

Text Solution

Verified by Experts

The correct Answer is:
`(2)/(Q)xx(100)/(30)xx(50)/(1.6xx10^(-19))xx(2)/(N_(A))xx10^(-3)Kg`
`=2.9xx10^(-7)kg` ;
where `Q=(2M_(1H_(2)^(2))-M_(2He^(4)))xx931=23.834531 MeV`
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