Atomic weight of boron is 10.81 and it h...

Atomic weight of boron is `10.81` and it has two isotopes `._5 B^10` and `._5 B^11`. Then ratio of `._5 B^10` in nature would be.

`19:81`

`10:11`

`15:16`

`81:19`

Text Solution

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The correct Answer is:

Let `._(5)^(10)B` and `._(5)^(11)B` be in the ratio `m:n`.
Average atomic weight
`10.81=(mxx10+nxx1)/(m+n)" "rArr(m)/(n)=(0.19)/(0.81)=(19)/(81)`

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B-10 isotopes

The natural boron of atomic weight 10.81 is found to have two isotopes .^10B and .^11B .The ratio of abundance of isotopes of natural boron should be

(a) Two stable isotope of ._3Li^6 and ._3Li^7 have respective abundances of 7.5% and 92.5% . These isotopes have masses 6.01512 and 7.01600 u respectively. Find the atomic weight of lithium. (b) Boron has two stable isotopes ._5B^(10) and ._5B^(11) . Their respective masses are 10.01294 u and 11.00931u, and the atomic weight of boron is 10.81u. Find the abundaces of ._5B^(10) and ._5B^(11) .

Assertion : Relative atomic mass of boron is 10.8 Reason : Boron has two isotopes B-10 and B-11 with percentage abundance of 19.6 % and 80.4 % respectively.

In each of the following two questions two statements are given one labelled as the Assertion(A) or Statement I and the other labelled as the reason (R) or statement II. Examine these statements carefully and mark the correct choice as per following instructions Assertion (A) - Relative atomic mass of boron is 10.8 Reason (R) - Boron has two isotopes B-10 and B-11 with percentage abundance of 19.6% and 80.4% respectively.

Statement-1 : Boron has relative atomic mass 10.81. Statement-2 : Boron has two isotopes ._5^10B and ._5^11B and their relative abundance is 19% and 81% .

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