Nuclei X decay into nuclei Y by emitting...

Nuclei `X` decay into nuclei `Y` by emitting `alpha`-aprticles. Energies of `alpha`-particle are found to be only `1 MeV` & `1.4 MeV`. Disregarding the recoil of nuclei `Y`. The energy of `gamma` photon emitted will be

`0.8 MeV`

`1.4 MeV`

`1 MeV`

`0.4 MeV`

Text Solution

Verified by Experts

The correct Answer is:

Energy of `gamma` photon
`=` Difference in energies of `alpha` particles `=0.4 MeV`

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