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In a fission reaction .92^236 U rarr ^11...

In a fission reaction `._92^236 U rarr ^117 X + ^117Y + n + n`, the binding energy per nucleon of `X` and `Y` is `8.5 MeV` whereas of `.^236 U` is `7.6 MeV`. The total energy liberated will be about.

A

`200 KeV`

B

`2 MeV`

C

`200 MeV`

D

`2000 MeV`

Text Solution

Verified by Experts

The correct Answer is:
C
`Q=(BE_(x)+BE_(y)-Be_(u))`
`=(2xx117xx8.5-236xx7.6)MeV=195 MeV~~ 195 MeV~~200 MeV`.
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