Calculate `DeltaH` (in atm-litre) for a real gas undergoing a change from (10 L, 20 atm) to (50 L,40 atm)
Given : `((delH)/(delP))_(v)=10 litre,((delH)/(delV))=5 atm`

Calculate DeltaU for a gas, if enthalpy change is 40 atm-L for the state change (5 atm, 10 L) to (3 atm,15 L) :

What amount of work is done if an ideal gas expands from 10 L of 20 L at 2 atm pressure?

One mole of non - ideal gas undergoes a change of state (1.0 atm, 3.0L, 200 K ) to (4.0 atm, 5.0L,250 K) with a change in internal energy (DeltaU)=40 L-atm . The change in enthalpy of the process in L-atm ,

One mole of non - ideal gas undergoes a change of state (1.0 atm, 3.0L, 200 K ) to (4.0 atm, 5.0L,250 K) with a change in internal energy (DeltaU)=40 L-atm . The change in enthalpy of the process in L-atm ,

One mole of non - ideal gas undergoes a change of state (1.0 atm, 3.0L, 200 K ) to (4.0 atm, 5.0L,250 K) with a change in internal energy (DeltaU)=40 L-atm . The change in enthalpy of the process in L-atm ,

One mole of a non-ideal gas undergoes a change of state from (2,0 atm, 3.0 L, 100 K) to (4.0 atm, 5.0 L, 250 K) with a change in internal energy, DeltaU=30.0 Latm. The change on enthalpy of process in (L - atm) is

One mole of a non-ideal gas undergoes a change of state from (2,0 atm, 3.0 L, 100 K) to (4.0 atm, 5.0 L, 250 K) with a change in internal energy, DeltaU=30.0 Latm. The change on enthalpy of process in (L - atm) is

Maximum heat absorbed during isothermal expansion of an ideal gas from (10 atm, 1 L) to (1 atm, 10 L) is :