Nucleus `._(3)A^(7)` has binding energy per nucleon of `10 MeV`. It absorbs a proton and its mass increases by `(90)/(100)` times the mass of proton. Find the new binding energy of the nucleus so formed. [Take energy equivalent of proton `= 930 MeV`]

Answer

`79.3 MeV`

Explanation

`BE`=Original Binding energy `+` Binding energy due to additional mass defect
`=70+(1)/(100)(930)=79.MeV`