If the surface area of a sphere of radius r is increasing uniformly at the rate `8(cm)^2/s`, then the rate of change of its volume is:

If the surface area of a sphere of radius ris increasing uniformly at the rate 8((cm)^(2))/(s), then the rate of change of its volume is:

If the surface area of a sphere of radius r is increasing uniformly at the rate cm^(2)//s , then the rate of change of its volume is :

The surface area of spherical balloon is increasing at the rate of 2cm^(2) /sec. Find the rate of change of its volume when its radius is 5cm

Radius of a sphere is increasing at the rate of 2 cm/s The rate of change of its volume, when radius is 6 cm, is

The rate of change of the surface area of a sphere of radius r when the radius is increasing at the rate of 2cm/sec is proportional to

The radius of a spherical soap bubble is increasing at the rate of 0.3cm/s. Find the rate of change of its: Volume when the radius is 8 cm.

The surface area of a spherical bubble is increasing at the rate of 2cm^(2)/s. When the radius of the bubble is 6cm at what rate is the volume of the bubble increasing?