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Suppose a pure Si-crystal has 5xx10^(28)...

Suppose a pure Si-crystal has `5xx10^(28) "atoms" m^(-3)`. It is doped by 1 ppm concentration of pentavalent As. Calculate the number of electrons and holes. Give that `n_(i)=1.5xx10^(16)m^(-3)`.

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Here `n_(e) ~~ N_(D)=((5 xx10^(28))/(10^(6)))=5 xx 10^(22)m^(-3),n_(h)=(n_(1)^(2))/(n_(e))=((1.5 xx 10^(16))^(2))/(5xx10^(22))=(2.25 xx 10^(32))/(5 xx10^(22))=4.5 xx 10^(9) m^(3)`.
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