An n-p-n transistor in a common emitter mode is used as a simple voltage amplifier with a collector connected to load resistance `R_(L)` and to the base through a resistance `R_(B)`. The collector-emmiter voltage `V_(CE) = 4V`, the base-emitter voltage `V_(BE) = 0.6 V`, current through collector is `4 mA` and the current amplification factor `beta = 100` Calculate the value of `R_(L)` and `R_(B)`.

Explanation

Given, `i_(c) = 4 mA` applying Kirchhoff's second law in loop 1.
`V_(CE)=8-I_(C) R_(L)rArr R_(L)=(8-V_(CE))/(i_(c))=(8-4)/(4 xx 10^(-3))=1 xx 10^(3) Omega =1 k Omega`
`I_(B) = (I_(C))/(beta) = (4 mA)/(100) = 4 xx 10^(-5)A`
`because V_(BE) =8-I_(B)R_(B)rArr R_(B)=(8-V_(BE))/(I_(B))=(8-06)/(4 xx 10^(-5))=185 k Omega`
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