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On cm on the main scale of vernier calli...

On cm on the main scale of vernier callipers is divided into ten equal parts. If 20 division of vernier scale coincide with 8 small divisions of the main scale. What will be the least count of callipers ?

Text Solution

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20 division of vernier scale = 8 division of main scale `rArr V.S.D = ((8)/(20))M.S.D = ((2)/(5))M.S.D`
`L.C = 1 M.S.D - 1 V.S.D = 1 M.S.D - ((2)/(5)) M.S.D = (-(2)/(5)) M.S.D`
`= (3)/(5) M.S.D=(3)/(5)xx0.1 cm =0.06cm(because 1M.S.D=(1)/(10)cm=0.1cm)`
Note : for objective question `L.C =M-V((b-a)/(b))M((20-8)/(20))((1)/(10))cm=(3)/(50)cm=0.06 cm`.
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