A sinusoidal voltage of amplitude 25 volts and frequency 50 Hz is applied to a half wave rectifier using PN diode. No filter is used and the load resistor is `1000 Omega`. The forward resistance `R_(f)` ideal diode is `10 Omega`. Calculate.
(i) Peak, average and rms values of load current
(ii) d.c power output
(ii) a.c power input
(iv) % Rectifier efficiency
(v) Ripple factor.

Explanation

To solve the problem step by step, we will calculate the required values for the half-wave rectifier using the given parameters.

### Given:
- Amplitude of voltage (V_peak) = 25 V
- Frequency (f) = 50 Hz
- Load resistance (R_L) = 1000 Ω
- Forward resistance of the diode (R_f) = 10 Ω

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