The halfwave rectifier supplies power to be `1 k Omega`. The input supply voltage is 220 V neglecting forward resistance of the diode, calculate
(i) `V_(dc)`
(ii) `I_(ac)` and
(iii) Ripple voltage (rms value)

Explanation

To solve the problem step by step, we will calculate the DC voltage, DC current, and ripple voltage for the half-wave rectifier supplying power to a load resistance of 1 kΩ with an input supply voltage of 220 V.

### Step 1: Calculate the Peak Voltage (V_peak)
The input supply voltage is given as RMS voltage (V_RMS = 220 V). To find the peak voltage (V_peak), we use the formula:
\[ V_{peak} = V_{RMS} \times \sqrt{2} \]

Substituting the given value:
\[ V_{peak} = 220 \times \sqrt{2} \]
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