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A fullwave P.N diode rectifier used load...

A fullwave P.N diode rectifier used load resistor of `1500 Omega`. No filter is used. Assume each diode to have idealized characteristic with `R_(f) = 10 Omega` and `R_(r) = ac`. Since wave voltage applied to each diode has amplitude of 30 volts and frequency 50 Hz. Calculate.
(i) Peak, d.c rms load current
(ii) d.c power input
(iii) A.C power input
(iv) Rectifier efficiency.

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To solve the problem step by step, we will calculate the required values based on the given information about the full-wave rectifier using a PN diode. ### Given Data: - Load Resistance, \( R_L = 1500 \, \Omega \) - Forward Resistance of each diode, \( R_f = 10 \, \Omega \) - Amplitude of applied voltage, \( V_m = 30 \, V \) - Frequency, \( f = 50 \, Hz \) ...
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