A Zener diode is specified having a breakdown voltage of 9.1 V with a maximum power dissipation of 364 mW. What is the maximum current that the diode can handle.

Explanation

To find the maximum current that a Zener diode can handle, we can use the relationship between power, voltage, and current. The formula we will use is:

\[ P = I \times V \]

Where:
- \( P \) is the power (in watts),
- \( I \) is the current (in amperes),
- \( V \) is the voltage (in volts).
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