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In npn transistor circuit, the collector...

In npn transistor circuit, the collector current us 10 mA. If 95 % of the electrons emitted reach the collector what is the free current ?

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`I_(c)=95 %,I_(c)=0.95I_(e):. I_(c) = (100)/(95)xxI_(c)=(100)/(95)xx10mA=10.53mA (because I_(c)=10mA)`
Now `I_(e)=I_(c)+I_(b):. I_(b)=I_(a)-I_(c)=10.53-10=0.53mA`
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