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The resultant amplitude, when two waves ...

The resultant amplitude, when two waves of two waves of same frequency but with amplitudes `a_(1)` and `a_(2)` superimpose at phase difference of `pi//2` will be :-

A

`a_(1) + a_(2)`

B

`a_(1) - a_(2)`

C

`sqrt(a_(1)^(2) + a_(2)^(2))`

D

`a_(1)^(2) + a_(2)^(2)`

Text Solution

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The correct Answer is:
C

`a=sqrt(a_(1)^(2)+a_(2)^(2)+2a_(1)a_(2)"cos"(pi)/(2))=sqrt(a_(1)^(2)+a_(2)^(2))`
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