The extension in a string, obeying Hooke's law, is x. The speed of sound in the stretched string is v. If the extension in the string is increased to `1.5 x`, the speed of sound will be :-

Options

A. 1.22 v
B. 0.61 v
C. 1.50 v
D. 0.75 v

Answer

A

Explanation

`vpropsqrt("Tension")rArrv=sqrt(kx)`
`v'=sqrt(k(1.5x))rArr(v')/(v)=sqrt(1.5)=1.22rArr v'=1.22v`.