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Frequency of tuning fork A is 256 Hz. It...

Frequency of tuning fork A is 256 Hz. It produces 4 beats/second with tuning fork B. When wax is applied at tuning fork B then 6 beats/second are heard. Frequency of B is :-

A

250 Hz

B

260 Hz

C

252 Hz

D

(A) & (C) both may possible

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The correct Answer is:
To find the frequency of tuning fork B, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Data:** - Frequency of tuning fork A (f_A) = 256 Hz - Beats produced with tuning fork B (initially) = 4 beats/second - Beats produced after applying wax on tuning fork B = 6 beats/second 2. **Understanding Beats:** - The number of beats per second is given by the absolute difference in frequencies of the two tuning forks. - Therefore, the relationship can be expressed as: \[ |f_A - f_B| = \text{Number of beats} \] 3. **Setting Up the Equation for Initial Beats:** - For the initial case (4 beats/second): \[ |256 - f_B| = 4 \] - This gives us two possible equations: 1. \(256 - f_B = 4\) → \(f_B = 256 - 4 = 252 \text{ Hz}\) 2. \(f_B - 256 = 4\) → \(f_B = 256 + 4 = 260 \text{ Hz}\) 4. **Possible Frequencies for B:** - From the above calculations, the possible frequencies for tuning fork B are: - \(f_B = 252 \text{ Hz}\) - \(f_B = 260 \text{ Hz}\) 5. **Analyzing the Effect of Wax:** - When wax is applied to tuning fork B, it increases the mass and thus decreases its frequency. - In this case, the number of beats increases to 6 beats/second: \[ |256 - f_B'| = 6 \] - This gives us two new possible equations: 1. \(256 - f_B' = 6\) → \(f_B' = 256 - 6 = 250 \text{ Hz}\) 2. \(f_B' - 256 = 6\) → \(f_B' = 256 + 6 = 262 \text{ Hz}\) 6. **Conclusion on Frequency of B:** - Since applying wax decreases the frequency of tuning fork B, we need to consider the case where the frequency of B was initially higher (260 Hz) and then decreased. - Thus, the only feasible frequency for tuning fork B that satisfies both conditions (initially producing 4 beats and then 6 beats after applying wax) is: \[ f_B = 252 \text{ Hz} \] ### Final Answer: The frequency of tuning fork B is **252 Hz**. ---

To find the frequency of tuning fork B, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Data:** - Frequency of tuning fork A (f_A) = 256 Hz - Beats produced with tuning fork B (initially) = 4 beats/second - Beats produced after applying wax on tuning fork B = 6 beats/second ...
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