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The equation of a wave travelling along ...

The equation of a wave travelling along the positive x-axis, as shown in figure at t=0 is given by :-
.

A

`sin (kx - omegat +(pi)/(6))`

B

`sin (kx - omega t-(pi)/(6))`

C

`sin (omega t - kx +(pi)/(6))`

D

`sin (omega t - kx-(pi)/(6))`

Text Solution

Verified by Experts

The correct Answer is:
D
`y=sin(omegat-kx+phi)`
`v=omegacos(omegat-kx+phi)`
at `t =0,x=0,y=-0.5,v gt 0 rArr phi = -(pi)/(6)`
`:. y=sin(omegat-kx-(pi)/(6))`
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