A source of sound is moving along a circular orbit of radius `3 meter` with an angular velocity of `10 rad//s`. A sound detector located far away from the source is executing linear simple harmonic motion along the line `BD` with an amplitude `BC = CD = 6 meters`. The frequency of oscillation of the detector is `(5)/(pi)` per second. The source is at the point `A` when the detector is at the point `B`. If the source emits a continuous sound wave of frequency `340 Hz`, Find the maximum and the minimum frequencies recorded by the detector.

Answer

`438.7 Hz,257.3 Hz`

Explanation

`f_(max)=f_(0)((v+v_(0))/(v+v_(s)))`
`=340((340+2pi((5)/(pi))6)/(340-10xx3))=438.7Hz`
`f_(min)=f_(0)((v-v_(0))/(v+v_(s)))=340((340-60)/(340+30))=257.3Hz`