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A harmonically moving transverse wave on...

A harmonically moving transverse wave on a string has a maximum particle velocity and acceleration of 3 m/s and `90 m//s^(2)` respectively. Velocity of the wave is `20 m//s`. Find the waveform.

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To find the waveform of a harmonically moving transverse wave on a string, we will follow these steps: ### Step 1: Understand the given parameters We are given: - Maximum particle velocity, \( V_{\text{max}} = 3 \, \text{m/s} \) - Maximum particle acceleration, \( A_{\text{max}} = 90 \, \text{m/s}^2 \) - Velocity of the wave, \( v = 20 \, \text{m/s} \) ### Step 2: Relate maximum particle velocity and acceleration to amplitude and angular frequency The maximum particle velocity is given by the formula: \[ V_{\text{max}} = A \omega \] where \( A \) is the amplitude and \( \omega \) is the angular frequency. The maximum particle acceleration is given by: \[ A_{\text{max}} = A \omega^2 \] ### Step 3: Set up the equations From the first equation, we have: \[ A \omega = 3 \quad \text{(1)} \] From the second equation, we have: \[ A \omega^2 = 90 \quad \text{(2)} \] ### Step 4: Divide equation (2) by equation (1) Dividing equation (2) by equation (1): \[ \frac{A \omega^2}{A \omega} = \frac{90}{3} \] This simplifies to: \[ \omega = 30 \, \text{rad/s} \] ### Step 5: Substitute \( \omega \) back to find \( A \) Substituting \( \omega = 30 \) into equation (1): \[ A \cdot 30 = 3 \] Thus, \[ A = \frac{3}{30} = 0.1 \, \text{m} \] ### Step 6: Use wave velocity to find wave number \( k \) The wave velocity is related to \( \omega \) and \( k \) by: \[ v = \frac{\omega}{k} \] Rearranging gives: \[ k = \frac{\omega}{v} \] Substituting the known values: \[ k = \frac{30}{20} = 1.5 \, \text{m}^{-1} \] ### Step 7: Write the wave equation The general form of the wave equation is: \[ y(x, t) = A \sin(kx + \omega t + \phi) \] Substituting the values of \( A \), \( k \), and \( \omega \): \[ y(x, t) = 0.1 \sin(1.5x + 30t + \phi) \] ### Final Waveform Equation Thus, the equation of the waveform is: \[ y(x, t) = 0.1 \sin(1.5x + 30t + \phi) \]

To find the waveform of a harmonically moving transverse wave on a string, we will follow these steps: ### Step 1: Understand the given parameters We are given: - Maximum particle velocity, \( V_{\text{max}} = 3 \, \text{m/s} \) - Maximum particle acceleration, \( A_{\text{max}} = 90 \, \text{m/s}^2 \) - Velocity of the wave, \( v = 20 \, \text{m/s} \) ...
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