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A transistor has an alpha = 0.95 It has ...

A transistor has an `alpha = 0.95` It has change in emitter current of 100 mili-ampere, then the change in collector current is :-

A

95 mA

B

99.05 mA

C

0.95 mA

D

100 mA

Text Solution

Verified by Experts

The correct Answer is:
A
`alpha=(DeltaI_(C))/(DeltaI_(E))rArr DeltaI_(C)=alpha DeltaI_(E)=0.95xx100 mA=95mA`
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ALLEN-SEMICONDUCTORS-Part-3(Exercise-1)
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