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The current of transistor in common emit...

The current of transistor in common emitter mode is 49. The change in collector current and emitter current corresponding to the change in the base current by `5.0 muA`m will be :-

A

`245 muA,250 muA`

B

`240 muA,235 muA`

C

`260 muA,255 muA`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
`beta=(DeltaI_(C))/(DeltaI_(B))rArrDeltaI_(C)=beta DeltaI_(B)=49xx5 muA=245muA`
`Delta I_(E)=DeltaI_(B)+DeltaI_(C)=5+245=250muA`
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