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The circuit has two oppsitely ideal diod...

The circuit has two oppsitely ideal diodes in parallel. What is the current flowing in the circuit.

A

1.71 A

B

2.00 A

C

2.31 A

D

1.33 A

Text Solution

Verified by Experts

The correct Answer is:
B
`I= (12)/(4+2)=2A`
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