Enthalpy of neutralization of `H_(3)PO_(3)` acid is- 106.68 kJ/mol using NaOH. If enthalpy of neutralization of HCl by NaOH is -55.84 kJ/mol. Calculate `Delta H_("ionization")` of `H_(3)PO_(3)` into its ions:

Enthalpy of neutralisation of H_(3)PO_(3) acid is -106.68kJ//mol using NaOH. If enthaly of neutralisation of HCl by NaOH is -55.84 kJ/mol. Calculate DeltaH_("ionization") " of " H_(3)PO_(3) into its ions

Enthalpy of neutralization of H_(3)PO_(3) "with " NaOH " is" -106.68 "kJ"//"mol" . If enthalpy of neutralization of HCL with NaOH is -55.84 "kJ"//"mole" , then calculate enthalpy of ionization of H_(3)PO_(3) in to its ions in kJ.

Enthalpy of neutralization of H_(3)PO_(3) "with " NaOH " is" -106.68 "kJ"//"mol" . If enthalpy of neutralization of HCL with NaOH is -55.84 "kJ"//"mole" , then calculate enthalpy of ionization of H_(3)PO_(3) in to its ions in kJ.

Enthalpy of neutralization of HCl by NaOH is -55.84 kJ/mol and by NH_(4)OH is 51.34 kJ/mol. The enthalpy of ionization of NH_(4)OH is :

Enthalpy of neutralization of HCl by NaOH is -55.84 kJ/mol and by NH_(4)OH is 51.34 kJ/mol. The enthalpy of ionization of NH_(4)OH is :

Enthalpy of neutralization of HCl by NaOH is -55.84 kJ/mol and by NH_(4)OH is -51.34 kJ/mol. The enthalpy of ionization of NH_(4)OH is :

If enthalpy of neutralisation of HCl by NaOH is -58.84 kJ/mol and by NH_4OH is -52.26 kJ/mol, then enthalpy of ionisation of NH_4OH is

Heat of neutralisation of a weak acid HA by NaOH is -"12.13 kJ mol"^(-1) . Calculate the enthalpy of ionization of HA.