Water potential of a flaccid cell will be

Options

A. `Psi_(w)=(psi_(p))`
B. `Psi_(w)=Psi_(s)`
C. `Psi_(s)=Psi_(rho)`
D. `Psi_(w)=0`

Answer

B

Explanation

If plant cell happens to be bathed in hypertonic solution, it loses water through the process of exosmosis. The loss of wate is first from cytoplasm and then central vacuole. As a result, the protoplast is reduced in size. This decreases turgor pressure or pressure potential `(psi_(p))` and corresponding wall pressure. solute potentail becomes slightly more negative due to loss of water. The cell attains a minimum size when turgor pressure is zero/pressure potential `(psi_(p))` is zero.
Therefore, `psi_(w) = psi_(s) + psi_(p)`
or `psi_(w) = psi_(s) (as psi_(p) = 0)`
A cell which is deficient in turgor is called flaccid.