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Water potential of a flaccid cell will b...

Water potential of a flaccid cell will be

A

`Psi_(w)=(psi_(p))`

B

`Psi_(w)=Psi_(s)`

C

`Psi_(s)=Psi_(rho)`

D

`Psi_(w)=0`

Text Solution

Verified by Experts

The correct Answer is:
B

If plant cell happens to be bathed in hypertonic solution, it loses water through the process of exosmosis. The loss of wate is first from cytoplasm and then central vacuole. As a result, the protoplast is reduced in size. This decreases turgor pressure or pressure potential `(psi_(p))` and corresponding wall pressure. solute potentail becomes slightly more negative due to loss of water. The cell attains a minimum size when turgor pressure is zero/pressure potential `(psi_(p))` is zero.
Therefore, `psi_(w) = psi_(s) + psi_(p)`
or `psi_(w) = psi_(s) (as psi_(p) = 0)`
A cell which is deficient in turgor is called flaccid.
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Knowledge Check

  • In a flaccid cell

    A
    DPD=OP
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    `Psi_(W)=Psi_(S)+(Psi_(P))`
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