In a fully turgid cell

Options

A. `Psi_(w)=Psi_(s)+Psi_(rho)`
B. `Psi_(w)=` zero
C. `Psi_(w)=-Psi_(s)-Psi_(rho)`
D. `Psi_(w)=Psi_(s)=Psi_(rho)`

Answer

B

Explanation

In case of fully turgid cell, the net movement of water into the cells is stopped. the cell is in equilibrium with the water outside. the water potential in such a case will be zero (0).
A cell at full turgor its osmotic potential and pressure potential equal but opposite in sign. Therefore, its water potential will be zero. For example a cell has its `psi_(s)` of - 10 bars and `psi_(p)` fo 10 bar, the resultant water potential will be zero as follows: `psi_(w) = psi_(s) + psi_(p)`
`psi_(w) = - `10 bars + 10 bars
`psi_(w) = 0` bars