A very long magnet is held vertically with its south pole on a table. A single neutral point is located on the table to the

A very long magneti is placed vertically with one pole on the table. A neutral point was found at 20 cm from the pole. What is the pole strength if the vertical component of earth's field is 0.4xx10^(-4)Wb//m^(2) ?

A bar magnet of length 8 cm and having a pole strengh of 1.0 A m is placed vertically on a horizontal table with its south pole on the table. A neutral point is found on the table at a distance of 6.0 cm north of the magnet. Calculate the earth's horizontal magnetic field.

A bar magnet of length 8 cm and having a pole strengh of 1.0 A m is placed vertically on a horizontal table with its south pole on the table. A neutral point is found on the table at a distance of 6.0 cm north of the magnet. Calculate the earth's horizontal magnetic field.

A bar magnet of length 8 cm and having a pole strengh of 1.0 A m is placed vertically on a horizontal table with its south pole on the table. A neutral point is found on the table at a distance of 6.0 cm north of the magnet. Calculate the earth's horizontal magnetic field.

A bar magnet of length 8 cm and having a pole strengh of 1.0 A m is placed vertically on a horizontal table with its south pole on the table. A neutral point is found on the table at a distance of 6.0 cm north of the magnet. Calculate the earth's horizontal magnetic field.

A very long magnet of pole strength 4 Am is placed vertically with its one pole on the table. The distance form the pole, the neutral point will be formed is (B_(H)=4xx10^(-5)T)

A small bar magnet is place horizontally in the magnetic meridian with its north pole pointing south ,. A neutral point is formed on the axis of the bar magnet at a distance of 24 cm from its south pole. If the horizontally component of earth's magnetic field is 0.18xx10^(-4) what will be the magnetic field at a distance of 20 cm north of the south pole?