Position time graph is shown which is a semicircle form `t = 2` to `t = 8sec`. Find time `t` at which the instantaneous velocity, is equal to average velocity over first `t` second.

A point moves rectilinearly in on direction. Figure shows the distance s traversed by the point as a function of the time t. Using the plot find: (a) the average velocity of the point during the time of motion, (b) the maximum velocity, (c) the time moment t_0 at which the instantaneous velocity is equal to the mean velocity averaged over the first t_0 seconds.

A particle moves in a straight line. Figure-1.21 shows the distance traversed by the particle as a function of time t .Using the graph, find (a)the average velocity of the point during the time of motion, (b) the maximum velocity, (c) the time t = t_(0) at which the instantaneous velocity is equal to the mean velocity averaged over the first t_(0) seconds.

Position time graph is given find average speed in time t=0 and t=15 sec is

Position time graph is given find average speed in time t=0 and t=15 sec is

Position time graph is given find average speed in time t=0 and t=15 sec is

The position of a particle is given by the function s(t)= 2 t^2 + 3t - 4. Find the time t=c in the interval 0 le t le 4 when the instantaneous velocity of the particle equals to its average velocity in this interval.

Position - time graph for a particle is shown in figure. Starting from t = 0, at what time t, the average velocity is zer?

Position - time graph for a particle is shown in figure. Starting from t = 0, at what time t, the average velocity is zer?

A particle is projected with a speed v and an angle theta to the horizontal. After a time t, the magnitude of the instantaneous velocity is equal to the magnitude of the average velocity from 0 to t. Find t.