" 31.Iffexe "={[(2^(x+2)-16)/(4^(x)-16)," if "x!=2],[k," if "x=2]" is continuous at "x=2" ,find "k

If f(x)={(2^(x+2)-16)/(4^(x)-16), if x!=2,k if x=2 is continuous at x=2, find k

f(x)={(2^(x+2)-16)/(4^(x)-16),quad if x!=2k,quad if x=2 is continuous at x=2, find k

If f(x)={(2^(x+2)-16)/(4^x-16) , if x!=2 , k if x=2 is continuous at x=2 , find k

If f(x)={(2^(x+2)-16)/(4^x-16),if x!=2k ,if f(x) is continuous a t x=2, find k

If f(x)={((2^(x+2)-16)/(4^x-16),x!=2),(k, x=2):} is continuous at x=2 , find k .

find the value of k, so that the function f(x)={((2^(x+2)-16)/(4^(x)-16)", if "x!=2),(k", if "x=2):} is continuous at x=2.

f(x)={(2^(x+2)-16)/(4^(x)-16),quad if x!=2 and k, if x=2 at x=2

f(x)= {((2^(x + 2)-16)/(4^(x)-16)",",x ne 2),(k",",x=2):} f(x) is continuous at x=2 then find k

Find the value of 'k', such that the function : f(x) = {:{(2x^(x+2)-16)/(4^x -16), if x ne2),(k, if x =2):} is continuous at x =2

If f(x) ={{:((2^(x+2)-16)/(4^(x)-16), if x ne 2 ),(k, if x = 2):} , is 'conti nuous' at x = 2 . then find 'k'.